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-4.9x^2-1.6x+4.7=0
a = -4.9; b = -1.6; c = +4.7;
Δ = b2-4ac
Δ = -1.62-4·(-4.9)·4.7
Δ = 94.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{94.68}}{2*-4.9}=\frac{1.6-\sqrt{94.68}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{94.68}}{2*-4.9}=\frac{1.6+\sqrt{94.68}}{-9.8} $
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